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Corroder
Grandmaster Cheater Supreme
 Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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 Posted: Fri Dec 16, 2016 9:05 pm Post subject: Maintain AOB replace have same length with AOB scan |
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Hi guys,
| Code: | search='46 ?? ?? ?? 11 13 00 00 60 ?? ?? 2c ?? ?? 4f ?? ?? ?? 24 01 5e ?? ?? 2b 61 ?? ?? 5d ?? ??'
change='46 ?? ?? ?? 11 00 00 00 60 ?? ?? 2c ?? ?? 29 29 02 02 24 14 5e ?? ?? 2b 61 ?? ?? 5d ?? ??'
aobs = search
function DEC_HEX(IN)
local B,K,OUT,I,D=16,"0123456789ABCDEF","",0
if IN<1 then
OUT=0
return OUT
end
while IN>0 do
I=I+1
IN,D=math.floor(IN/B),math.fmod(IN,B)+1
OUT=string.sub(K,D,D)..OUT
end
return OUT
end
if(aobs == nil) then
showMessage("No AOB to check")
else
for i = 1, string.len(change), 3 do
z = string.sub(change, i, i+2)
x, y = string.find(z, "%?+")
if (x == nil) then
script=[[
]].."+"..(DEC_HEX((i-1)/3))..[[:
db ]]..z..[[
]]
autoAssemble(script)
print(script)
end
end
object_destroy(aobs);
aobs=nil
end
--- result
+0:
db 46
+4:
db 11
+5:
db 00
+6:
db 00
+7:
db 00
+8:
db 60
+B:
db 2c
+E:
db 29
+F:
db 29
+10:
db 02
+11:
db 02
+12:
db 24
+13:
db 14
+14:
db 5e
+17:
db 2b
+18:
db 61
+1B:
db 5d
-- seem like '46 ?? ?? ?? 11 13 00 00 60 ?? ?? 2c ?? ?? 4f ?? ?? ?? 24 01 5e ?? ?? 2b 61 ?? ?? 5d ?? ??'
has replaced with '46 ?? ?? ?? 11 00 00 00 60 ?? ?? 2c ?? ?? 29 29 02 02 24 14 5e ?? ?? 2b 61 ?? ?? 5d ?? ??'
-- Now if :
search = 'd0 30 28 d6 20 63 06 '
change = '26 48 '
-- with same function above, give result
+0:
db 26
+1:
db 48
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from 2nd result, how to maintain given result print as '26 48 28 d6 20 63 06' ?. Meant AOB's not replaced also including when print it and also checking both AOB have same length.
Thanks
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panraven
Grandmaster Cheater
![]() Reputation: 62
Joined: 01 Oct 2008
Posts: 958
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| Posted: Fri Dec 16, 2016 9:45 pm Post subject: |
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Insert trailing wildcard to make it fit?
| Code: |
search = 'd0 30 28 d6 20 63 06 '
change = '26 48 ?? ?? ?? ?? ??'
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Since ce 6.5 (or ce 6.4?) support wildcard in db lines, so may be simply:
| Code: |
local aob = AOBScan(search)
if aob then
for i=0,aob.Count-1 do
autoAssemble(aob[i]..':\ndb '..change)
end
aob.Destroy()
end
|
unless your code is testing other thing.
bye~
_________________
- Retarded. |
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Zanzer
I post too much
![]() Reputation: 126
Joined: 09 Jun 2013
Posts: 3278
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| Posted: Fri Dec 16, 2016 10:41 pm Post subject: |
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Are you trying to do this? http://forum.cheatengine.org/viewtopic.php?p=5620925
| Code: | local replace = "26 ?? 48"
local count = 0
local script = ""
for byte in replace:gmatch("%S+") do
if byte ~= "??" then
script = script .. string.format("+%X:\r\ndd %s\r\n", count, byte)
end
count = count + 1
end
print(script) |
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Corroder
Grandmaster Cheater Supreme
Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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| Posted: Fri Dec 16, 2016 11:52 pm Post subject: |
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Thanks both Panraven and Zanzer
@Panraven : Yes it's better to use wildcard "??" put as not replacing AOB and maintain same AOB length both scan and replace
@Zanzer
| Code: | $lua}
if syntaxcheck then return end
cheat_name = "MyCheat"
[ENABLE]
..
..
[DISABLE]
|
Where put the script ?. In Cheat Engine Table or AA ?. I am not understand with this "{$lua} and "[ENABLE] [DISABLE]" statement.
| Code: | // eq.
scan="27 D0 30 66 C1 2C"
local replace = "26 ?? 48"
local count = 0
local script = ""
for byte in replace:gmatch("%S+") do
if byte ~= "??" then
script = script .. string.format("+%X:\r\ndb %s\r\n", count, byte)
end
count = count + 1
end
print(script)
// result
+0:
db 26
+2:
db 48 |
how to print script (result) with format "26 ?? 48 ?? ?? ??" ?. I mean ignoring aob count / bytes position and "db" to be print, something like concatenate replace aob with add wildcard "??" for the rest aob not replaced.
Thank you and regards
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panraven
Grandmaster Cheater
![]() Reputation: 62
Joined: 01 Oct 2008
Posts: 958
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| Posted: Sat Dec 17, 2016 12:44 am Post subject: |
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Padding wildcard to aob to a length if shorter?
| Code: |
function cntAobBytes(aob)
local cnt = 0
for _ in aob:gmatch"%S%S?" do cnt=cnt+1 end
return cnt
end
function padAob(aob,n)
n = type(n)=='string' and cntAobBytes(n) or n
return aob..string.rep(" ??",n-cntAobBytes(aob))
end
print(padAob("26 ?? 48",6))
print(padAob("26 ?? 48","27 D0 30 66 C1 2C"))
print(padAob(" 1 ? 3",6))
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Corroder
Grandmaster Cheater Supreme
Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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| Posted: Sat Dec 17, 2016 1:24 am Post subject: |
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Nah,...thank so much Panraven
This is I am looking for.
| Code: | function cntAobBytes(aob)
local cnt = 0
for _ in aob:gmatch"%S%S?" do cnt=cnt+1 end
return cnt
end
function padAob(aob,n)
n = type(n)=='string' and cntAobBytes(n) or n
return aob..string.rep(" ??",n-cntAobBytes(aob))
end
print(padAob("26 ?? 48",6))
print(padAob("26 ?? 48","27 D0 30 66 C1 2C"))
print(padAob(" 1 ? 3",6))
26 ?? 48 ?? ?? ??
26 ?? 48 ?? ?? ??
1 ? 3 ?? ?? ?? |
So, n mean is AOB length.
Thanks and regard
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Zanzer
I post too much
![]() Reputation: 126
Joined: 09 Jun 2013
Posts: 3278
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| Posted: Sat Dec 17, 2016 7:32 am Post subject: |
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Yes, my Lua in the other post is added as an AA script.
The {$lua} tells CE to interpret the code as Lua instead of assembly.
So it will execute the Lua when the user enables the script.
Performing the replace when its enabled and undoing it when disabled.
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Corroder
Grandmaster Cheater Supreme
Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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| Posted: Sat Dec 17, 2016 8:32 am Post subject: |
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Understood and thanks for helped
Regards
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