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Scan and replace double value (again)

 
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Corroder
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Joined: 10 Apr 2015
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PostPosted: Fri Oct 16, 2015 9:17 pm    Post subject: Scan and replace double value (again) Reply with quote

I read this function from mgr.inz.Player

Code:

function findDoubleValueAndReplace(findValue, replaceWith)
  memscan = createMemScan()
  foundlist = createFoundList(memscan)
  protectionflags = "-W*X-C"

  -- firstScan(scanoption, vartype, roundingtype, input1, input2,
  --           startAddress, stopAddress, protectionflags,
  --           alignmenttype, "alignmentparam",
  --           isHexadecimalInput, isNotABinaryString, isunicodescan, iscasesensitive)

  --    scanOption: soUnknownValue, soExactValue, soValueBetween, soBiggerThan, soSmallerThan
  --    vartype: vtByte, vtWord, vtDword, vtQword, vtSingle, vtDouble, vtString,
  --             vtByteArray, vtGrouped, vtBinary, vtAll
  --    roundingtype: rtRounded, rtTruncated, rtExtremerounded
  --    alignmenttype: fsmNotAligned, fsmAligned, fsmLastDigits
  --    protectionflags: X W C   (+ to indicate that flag MUST be set, - MUST NOT, * whatever)

  memscan.firstScan(soExactValue, vtDouble, rtTruncated, findValue, nil,
               "0","7fffffff",protectionflags,
               fsmAligned,"4",
               false, false, false, false)
  memscan.waitTillDone()
  foundlist.initialize()

  for i=0,foundlist.Count-1 do
   fullAccess(  getAddress(foundlist.Address[i])  , 8)
   writeDouble(  foundlist.Address[i], replaceWith)
  end

  sleep(50)
  foundlist.destroy()
  sleep(50)
  memscan.destroy()

end

--- used  example
a=findDoubleValueAndReplace(0.01, -0.04)
print(a)


Question :
1. Is there any way we get/ filter scan result that exactly 0.01 ?
2. What is different protectionflags = "-W*X-C" / "-W*X*C" / "-W*X+C" ?
3. From Cheat Engine Help file:

Quote:

rtRounded : Normal rounded scans. If exact value = "3" then it includes 3.0 to 3.49999999. If exact value is "3.0" it includes 3.00 to 3.0499999999
rtTruncated: Truncated algoritm. If exact value = "3" then it includes 3.0 to 3.99999999. If exact value is "3.0" it includes 3.00 to 3.099999999
rtExtremerounded: Rounded Extreme. If exact value = "3" then it includes 2.0000001 to 3.99999999. If exact value is "3.0" it includes 2.900000001 to 3.099999999


Shown we can;t get exact value as we need (in this case 0.01).
How if we get all result scan first, put all as string, filtering the string for 0.01 and return it to number and last use it as replace value ?.
If possible, does any one should make a function for usage it ?

Regards
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Zanzer
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PostPosted: Fri Oct 16, 2015 10:02 pm    Post subject: Reply with quote

Scan for vtQword with value 0x3F847AE147AE147B instead?
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mgr.inz.Player
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PostPosted: Sat Oct 17, 2015 5:21 am    Post subject: Reply with quote

For that use a string instead of a number, and append few zeroes:

Code:
findDoubleValueAndReplace("0.0100000", -0.04)



Or make scan for "array of bytes" type.

"7B 14 AE 47 E1 7A 84 3F" == 0.01 double

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Corroder
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Joined: 10 Apr 2015
Posts: 1668

PostPosted: Sat Oct 17, 2015 9:42 am    Post subject: Reply with quote

vtQword, ah yes need to try this also shall to try with vtDword.
Thank Zanzer for hint.


mgr.inz.Player, i did changed the double value 0.01 (AOB = 7B 14 AE 47 E1 7A 84 3F) to -0.04 (AOB = 7B 14 AE 47 E1 7A A4 BF)
I post this topic to get know a way how get exact value from scan double value if possible.
Anyhow, use

Code:

findDoubleValueAndReplace("0.0100000", -0.04)


also very helpful to reduce number of scan results found.
Thank you
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