Cheat Engine

[vergilganesh]

The game is prototype in this the max health is seperated in two addresses.

[mgr.inz.Player]

You are using wrong instructions.
1000.0 = 447A0000 (as hex integer) = 1148846080 (as decimal unsigned integer)
2700.0 = 4528C000 (as hex integer) = 1160298496 (as decimal unsigned integer)


1148846080 + 1160298496 = 2309144576 = 89A2C000 (as hex integer) = -3.918063731E-33

Your code is overwriting health value with very small value, value which is below zero and very close to zero.





You should use floating-point instructions:

[_Veggy]

You could simply use:

mov eax, [MaxHealth]
mov [CurrentHealth], eax

Considering your code:
mov eax,[esi+<..>] //Max health?
mov [esi+0c],eax

Which game is this for?

Here is a snippet from my trainer source for Devil May Cry 3.

cmp byte ptr [HealthFlag],01h
jne OriginalHealth
push eax
mov eax, [ebp+2a20h]
mov [ebp+2a4ch],eax
pop eax
OriginalHealth:
push 59b7afh
ret
nop
nop

[vergilganesh]

The code given by mgr.inz.player is worked for me. The game is prototype. Maximum health is seperated in 3 instructions.
max health = [esi+10]+[esi+14]+[esi+1F8] (2700+1000+200). I already hacked devil may cry 3. This is the code for god mode cheat.