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Still can't work out the Registered symbol thing...

 
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LykanthricAura
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Joined: 17 May 2010
Posts: 58
Location: India
PostPosted: Tue Nov 29, 2011 12:43 am    Post subject: Still can't work out the Registered symbol thing... Reply with quote
Ok. Here's the original instruction...

Code:
mov edx,[esi+0000008C]


Where...

esi = 3240094 (the address of the Unit's structure)
edx = E6 (230 ...the value Im working on)

So... If I did..

Code:
push edx
mov edx,[esi]
mov [pHero],edx
pop edx


That shud give me 3240094 in pHero right? or...Is that not how it works?
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Dark Byte
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Location: The netherlands
PostPosted: Tue Nov 29, 2011 2:56 am    Post subject: Reply with quote
no, this writes the first 4 byte value from the unit's structure into pHero (vtable)

Instead of
Code:

push edx
mov edx,[esi]
mov [pHero],edx
pop edx

you just do:
Code:

mov [pHero],esi


Note that pHero must be an allocated block of memory (at least 4 bytes) that has it's name registered.

So in a previous script (or the same one)
Code:

alloc(pHero,4)
registersymbol(pHero)

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LykanthricAura
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Joined: 17 May 2010
Posts: 58
Location: India
PostPosted: Wed Nov 30, 2011 12:20 am    Post subject: Reply with quote
If I do

alloc(pHero,4)

I cannot do label(pHero) ??? (made the script un-toggle-able)

I suppose we can't. I know...But why?

Allocated memory can't be a label?
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Geri
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Posts: 5627
PostPosted: Wed Nov 30, 2011 1:04 am    Post subject: Reply with quote
LykanthricAura wrote:
If I do

alloc(pHero,4)

I cannot do label(pHero) ??? (made the script un-toggle-able)

I suppose we can't. I know...But why?

Allocated memory can't be a label?


If you want to do that, use globalalloc.

globalalloc(pHero,4)

It will allocate the space + register it as a symbol.
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