| View previous topic :: View next topic |
| Author |
Message |
AverageAzn247
Grandmaster Cheater
 Reputation: 34
Joined: 01 Oct 2007
Posts: 909
Location: Austin,TX with 72 virgins
|
 Posted: Sat Apr 16, 2011 10:08 am Post subject: python help |
 |
|
I am supposed to write a program that compares txt files and tells where the first different is by line and column. I am able to find it by line but how would I find it by column? use .split(" ") ?
http://www.mediafire.com/?7m4brllzzbnddzc
_________________
| Waxxup wrote: | What are Night Elves?
A girl group? |
|
|
| Back to top |
|
 |
atom0s
Moderator
 Reputation: 205
Joined: 25 Jan 2006
Posts: 8587
Location: 127.0.0.1
|
| Posted: Sat Apr 16, 2011 3:00 pm Post subject: |
|
|
I don't use python but a method would be to:
1. Split each file into separate lines.
2. Compare line by line (full line compare.)
-- If matched, continue to next line.
-- If no match, step into each line letter by letter.
If python lets you do indexing on a string you can try doing that. If not, use split or substring (which ever they support) and pull 1 character at a time, increasing the position 1 by 1.
See:
http://docs.python.org/release/2.5.2/lib/string-methods.html
A method of reading char by char:
http://mail.python.org/pipermail/tutor/2006-August/048830.html
_________________
- Retired. |
|
| Back to top |
|
|
AverageAzn247
Grandmaster Cheater
Reputation: 34
Joined: 01 Oct 2007
Posts: 909
Location: Austin,TX with 72 virgins
|
| Posted: Sun Apr 17, 2011 12:48 pm Post subject: |
|
|
i did break it by line but the problem is that i can't figure out how to do it character by character since i converted everything into a list rather than str
_________________
| Waxxup wrote: | What are Night Elves?
A girl group? |
|
|
| Back to top |
|
|
AhMunRa
Grandmaster Cheater Supreme
![]() Reputation: 27
Joined: 06 Aug 2010
Posts: 1117
|
| Posted: Tue Apr 19, 2011 9:13 am Post subject: |
|
|
regex.match()
string.find()
string.count()
Should be what you are looking for.
If you like Python give this site a try. http://www.pythonchallenge.com/ Learned alot there.
Not quite what you are doing but may give you some ideas. Wrote this in 06
| Code: |
# emlremove.py
# Author **********
# Date 27 September 2006
# Last Edit 28 September 2006
# usage: emlremove.py > <FILEIN> <NAMES TO REMOVE> <FILEOUT>
#
# Parses a raw dump of user accounts, array line
# Compares the dump to an array of names to remove
# Names to remove includes past compiles and dead
# accounts.
# Also includes the @company domain.
#
# MODIFICATION:
#
# Added check on file out.
# If no data was written to fileout,
# File is deleted. Added confirmation screens.
def remove( firstArg, secondArg, thirdArg ):
import re, string, os
# OPEN OUR FILES FOR READING AND/OR WRITING
filea = open(firstArg, 'r')
fileb = open(secondArg, 'r')
filec = open(thirdArg, 'w')
# SANITY CHECK
success = ""
# MOVE CONTENTS OF FILES INTO A LIST PLACEHOLDER
line = filea.readlines()
names = fileb.readlines()
# SANITY CHECK
matches = ""
# CHECK FOR WETHER OR NOT WE ACTUALLY WROTE DATA TO filec
didWeWrite = "FALSE"
for l in line:
# STRIP THE NEWLINE CHAR FROM EACH ELEMENT OF OUR LIST
# WE DO THIS BECAUSE A NEWLINE IS READ IN BY readlines()
l = string.replace(l, "\n", "")
for n in names:
# AGAIN WITH THE STRIPPING
n = string.replace(n, "\n", "")
# IF ELEMENT l IS EQUAL TO ELEMENT n WE HAVE A MATCH
if l == n:
matches = "TRUE"
elif matches == "TRUE":
# IF WE MATCH SANITY CHECK SHOULD NOT PASS
success = "FALSE"
else:
# IF WE ARE NOT EQUAL SANITY CHECK SHOULD PASS
if l != n:
success = "TRUE"
else:
success = "FALSE"
# IF WE ARE SANE LET'S PRINT OUT OUR LIST AND APPEND THE DOMAIN ADDRESS
if success == "TRUE":
didWeWrite = "TRUE"
if l != "uyser":
filec.write(l + "@domain.com\n")
else:
pass
# RESETTING OUR SANITY CHECKS
success = ""
matches = ""
# TIDY UP OPEN FILES
filea.close()
fileb.close()
filec.close()
# DELETE UNEEDED FILE (WHICH IS OUR INFILE)
#os.remove(firstArg)
# DID WE WRITE CHECK
if didWeWrite == "FALSE":
print '''\n--------------------\n\n
NO NEW NAMES TO ADD\n\n
--------------------'''
os.remove(thirdArg)
else:
print '''\n--------------------\n\n
NEW USERS FOUND...
WRITING DATA TO...
.... %s ....\n\n
--------------------''' % thirdArg
# OUR MAIN ENTRY POINT
if __name__ == "__main__":
import sys
# IF INCORRECT NUMBER OF ARGS USED WE SHOW USAGE SCREEN
if len(sys.argv) != 4:
print '''\n********************\n\n
NAME: emlremove.py
AUTHOR: *********
DATE: 27 September 2006\n
Usage suggestion:\n
emlremove.py arg1 arg2 arg3\n
\n
For example:\n
C:\Python24\emlremove.py <READ FILE IN> <NAMES TO REMOVE> <SAVE TO>\n
********************'''
# IF CORRECT NUMBER OF ARGS USED WE RUN
else:
remove(sys.argv[1], sys.argv[2], sys.argv[3])
|
_________________
<Wiccaan> Bah that was supposed to say 'not saying its dead' lol. Fixing >.> |
|
| Back to top |
|
|
AverageAzn247
Grandmaster Cheater
Reputation: 34
Joined: 01 Oct 2007
Posts: 909
Location: Austin,TX with 72 virgins
|
| Posted: Tue Apr 19, 2011 9:29 pm Post subject: |
|
|
i figured it out. Turns out i have to store it into a new list for the characters.
_________________
| Waxxup wrote: | What are Night Elves?
A girl group? |
|
|
| Back to top |
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
