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will354
How do I cheat?
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Joined: 14 Dec 2024
Posts: 6
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 Posted: Sat Dec 14, 2024 12:30 pm Post subject: [Need Help] Find the Static Address of the Instruction |
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Please help me, How to find the static address of the instruction? I want to get the RIP register since that register store the static address. I want to implement the address into cheat table like this:
* look at attachment file 1 *
to this:
* look at attachment file 2 *
i can't do that because the address changed when re-open the game.
*disclaimer* the address not only 100156CC nor 100156D0, but the address range is like 10015000-10015FFF(?).
Thank you
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123.97 KB |
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3495 Time(s) |
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ParkourPenguin
I post too much
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Joined: 06 Jul 2014
Posts: 4697
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| Posted: Sat Dec 14, 2024 12:56 pm Post subject: |
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Use Template -> AOB Injection
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I don't know where I'm going, but I'll figure it out when I get there. |
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will354
How do I cheat?
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Joined: 14 Dec 2024
Posts: 6
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| Posted: Sat Dec 14, 2024 7:11 pm Post subject: |
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How i can perform function like "find out what writes to this address" in cheat table code? Because AOB only appear when i did "find out what writes to this address" in health pointer.
* look at attachment file *
| Description: |
| AOB Scan no result ("find out what writes to this address" is not press yet) |
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| Filesize: |
42.31 KB |
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3443 Time(s) |
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| Description: |
| The AOB Scan give a result when pressed "find out what writes to this address" |
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| Filesize: |
72.78 KB |
| Viewed: |
3443 Time(s) |
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ParkourPenguin
I post too much
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Joined: 06 Jul 2014
Posts: 4697
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| Posted: Sat Dec 14, 2024 8:04 pm Post subject: |
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Right click in the area with the checkboxes Writable, Executable, and CopyOnWrite. Clilck "Preset: scan all memory"
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I don't know where I'm going, but I'll figure it out when I get there. |
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will354
How do I cheat?
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Joined: 14 Dec 2024
Posts: 6
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| Posted: Sat Dec 14, 2024 10:47 pm Post subject: |
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Ok thank you, the scan worked now. But i have new issue now, the game crash when i used the aob injection (the injection only work on code injection, bit wierd or actually my cheat table code is not valid #cmiiw), how can i put the address result from aob scan into code injection address in cheat table framwork code?
| Code: |
[ENABLE]
// rev the code thank to DarkByte
//code from here to '[DISABLE]' will be used to enable the cheat
aobscan(INJECT,48 89 4A 78 4C 8B 44 24 10) // should be unique
alloc(newmem,$1000,INJECT)
label(code)
label(return)
newmem:
cmp [rdx+78+264], 0
jne code
mov [rdx+78],rcx
mov r8,[rsp+10]
jmp return
code:
mov [rdx+78],0
mov r8,[rsp+10]
jmp return
INJECT:
jmp newmem
nop 4
return:
registersymbol(INJECT)
[DISABLE]
//code from here till the end of the code will be used to disable the cheat
INJECT:
db 48 89 4A 78 4C 8B 44 24 10
unregistersymbol(INJECT)
dealloc(newmem)
{
// ORIGINAL CODE - INJECTION POINT: 10C017C3
10C01780: 48 BB 78 B3 9B 44 FF 7F 00 00 - mov rbx,libil2cpp.so.1+2DC7378
10C0178A: 48 89 9D 60 01 00 00 - mov [rbp+00000160],rbx
10C01791: FF 25 19 E3 E1 FF - jmp qword ptr [10A1FAB0]
10C01797: C7 85 20 0B 00 00 78 BA 67 03 - mov [rbp+00000B20],libunity.so+2DBA78
10C017A1: 48 8B 95 08 01 00 00 - mov rdx,[rbp+00000108]
10C017A8: 48 8B B2 80 00 00 00 - mov rsi,[rdx+00000080]
10C017AF: 48 89 B5 B8 00 00 00 - mov [rbp+000000B8],rsi
10C017B6: 4C 89 F9 - mov rcx,r15
10C017B9: 4C 89 BD B0 00 00 00 - mov [rbp+000000B0],r15
10C017C0: 49 29 F7 - sub r15,rsi
// ---------- INJECTING HERE ----------
10C017C3: 48 89 4A 78 - mov [rdx+78],rcx
// ---------- DONE INJECTING ----------
10C017C7: 4C 8B 44 24 10 - mov r8,[rsp+10]
10C017CC: 4C 89 85 10 01 00 00 - mov [rbp+00000110],r8
10C017D3: 48 8B 54 24 18 - mov rdx,[rsp+18]
10C017D8: 48 89 95 08 01 00 00 - mov [rbp+00000108],rdx
10C017DF: 48 8B 7C 24 00 - mov rdi,[rsp+00]
10C017E4: 48 89 BD 60 01 00 00 - mov [rbp+00000160],rdi
10C017EB: 4C 8B 4C 24 08 - mov r9,[rsp+08]
10C017F0: 4C 89 8D 18 01 00 00 - mov [rbp+00000118],r9
10C017F7: 48 8D 64 24 20 - lea rsp,[rsp+20]
10C017FC: 48 89 F9 - mov rcx,rdi
}
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| Description: |
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| Filesize: |
123.97 KB |
| Viewed: |
3418 Time(s) |
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Last edited by will354 on Sun Dec 15, 2024 11:45 am; edited 1 time in total |
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Dark Byte
Site Admin
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Joined: 09 May 2003
Posts: 25785
Location: The netherlands
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| Posted: Sun Dec 15, 2024 11:23 am Post subject: |
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where is exit ?
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Do not ask me about online cheats. I don't know any and wont help finding them.
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will354
How do I cheat?
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Joined: 14 Dec 2024
Posts: 6
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| Posted: Sun Dec 15, 2024 12:28 pm Post subject: |
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Thank you for the correction, i fixed the code and work perfectly. I figure it out, the problem is my array of byte not static, i search it with this 48 89 ?? 78 ?? 8B ?? 24 10, it work, but the instruction is not same as static byte, i mean the register is changed, how to deal with this situation? what should i write to dynamic aob? should i use like this?
| Code: |
[ENABLE]
// rev the code thank to DarkByte
//code from here to '[DISABLE]' will be used to enable the cheat
aobscan(INJECT,48 89 ?? 78 ?? 8B ?? 24 10) // should be unique
alloc(newmem,$1000,INJECT)
label(code)
label(return)
newmem:
cmp [rdx+78+264], 0
jne code
mov [rdx+78],rcx
?? // mov r8,[rsp+10]; the game sometime change the r8 register to another type register like rsi or something. Should i put the "??" in this line?
jmp return
code:
mov [rdx+78],0
?? // mov r8,[rsp+10]; the game sometime change the r8 register to another type register like rsi or something. Should i put the "??" in this line?
jmp return
INJECT:
jmp newmem
nop 4
return:
registersymbol(INJECT)
[DISABLE]
//code from here till the end of the code will be used to disable the cheat
INJECT:
db 48 89 ?? 78 ?? 8B ?? 24 10
unregistersymbol(INJECT)
dealloc(newmem)
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ParkourPenguin
I post too much
Reputation: 152
Joined: 06 Jul 2014
Posts: 4697
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will354
How do I cheat?
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Joined: 14 Dec 2024
Posts: 6
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| Posted: Sun Dec 15, 2024 11:23 pm Post subject: |
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ok thank you very much to @ParkourPenguin and @Dark Byte, the code is working now. My last question, how this number is calculated? because its look like nop the last 5 byte.
additional info if needed:
| Code: |
{
// ORIGINAL CODE - INJECTION POINT: 104C2F73-3 // old first inject point i got
104C2F30: 48 BB 78 73 BC 44 FF 7F 00 00 - mov rbx,libil2cpp.so.1+2DC7378
104C2F3A: 48 89 9D 60 01 00 00 - mov [rbp+00000160],rbx
104C2F41: FF 25 49 B1 E9 FF - jmp qword ptr [1035E090]
104C2F47: C7 85 20 0B 00 00 58 20 02 03 - mov [rbp+00000B20],03022058
104C2F51: 48 8B 95 08 01 00 00 - mov rdx,[rbp+00000108]
104C2F58: 48 8B B2 80 00 00 00 - mov rsi,[rdx+00000080]
104C2F5F: 48 89 B5 B8 00 00 00 - mov [rbp+000000B8],rsi
104C2F66: 4C 89 F9 - mov rcx,r15
104C2F69: 4C 89 BD B0 00 00 00 - mov [rbp+000000B0],r15
// ---------- SCAN PATTERN FROM HERE ---
104C2F70: 49 29 F7 - sub r15,rsi
// ---------- INJECTING HERE ----------
104C2F73: 48 89 4A 78 - mov [rdx+78],rcx
// ---------- DONE INJECTING ----------
104C2F77: 4C 8B 44 24 10 - mov r8,[rsp+10]
104C2F7C: 4C 89 85 10 01 00 00 - mov [rbp+00000110],r8 // looks like it nop this byte 85 10 01 00 00
// end to this byte, so from address 104C2F70 to 104C2F7C
104C2F83: 48 8B 54 24 18 - mov rdx,[rsp+18]
104C2F88: 48 89 95 08 01 00 00 - mov [rbp+00000108],rdx
104C2F8F: 48 8B 7C 24 00 - mov rdi,[rsp+00]
104C2F94: 48 89 BD 60 01 00 00 - mov [rbp+00000160],rdi
104C2F9B: 4C 8B 4C 24 08 - mov r9,[rsp+08]
104C2FA0: 4C 89 8D 18 01 00 00 - mov [rbp+00000118],r9
104C2FA7: 48 8D 64 24 20 - lea rsp,[rsp+20]
104C2FAC: 48 89 F9 - mov rcx,rdi
}
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| Description: |
| how this nop calculation actually work? |
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| Filesize: |
37.13 KB |
| Viewed: |
3275 Time(s) |
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ParkourPenguin
I post too much
Reputation: 152
Joined: 06 Jul 2014
Posts: 4697
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| Posted: Mon Dec 16, 2024 12:24 pm Post subject: |
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Looks like CE couldn't allocate memory nearby, so it used the 14-byte `jmp` instead. (or you told CE to do that)
Either way, `jmp newmem` should be `jmp far newmem` to guarantee a 14-byte `jmp`. If by random chance memory near `aobBaseAddress` is used, a 5-byte `jmp` would be automatically used and bad things happen.
`nop 5` is used to align the `return` label properly.
| Code: | 104C2F70: 49 29 F7 - sub r15,rsi - 3 bytes; not enough
104C2F73: 48 89 4A 78 - mov [rdx+78],rcx - 7 bytes; not enough
104C2F77: 4C 8B 44 24 10 - mov r8,[rsp+10] - 12 bytes; not enough
104C2F7C: 4C 89 85 10 01 00 00 - mov [rbp+00000110],r8 - 19 bytes; 19-14 = 5 bytes to `nop` |
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I don't know where I'm going, but I'll figure it out when I get there. |
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will354
How do I cheat?
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Joined: 14 Dec 2024
Posts: 6
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| Posted: Tue Dec 17, 2024 1:49 am Post subject: |
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thank you for the explanation @ParkourPenguin 
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