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ｃｄ&
Newbie cheater
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Joined: 08 Apr 2023
Posts: 20
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 Posted: Fri Jul 19, 2024 2:00 am Post subject: why readBytes(address,2,false) == readBytes(address,1,false) |
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I want bytes form addresses.
so, I write readBytes(address,16) .
but code returns not multiple bytes but single number.
celua.txt says :readByte() returns the bytes at the given address. If ReturnAsTable is true it will return a table instead of multiple bytes
Reads the bytes at the given address and returns a table containing the read out bytes
I don't understand it. Is it bug?
example:
address 12569ec0 12569ec1 .........
value 6c fd .........
readBytes(12569ec0,2,true) ={20,22}
and it shuld be readBytes(12569ec0,1,false) =20,readBYtes(12569ec0,2,false) =2220
but readBytes(12569ec0,1,false)=readBytes(12569ec0,2,false) =20 |
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Dark Byte
Site Admin
 Reputation: 468
Joined: 09 May 2003
Posts: 25711
Location: The netherlands
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| Posted: Fri Jul 19, 2024 2:43 am Post subject: |
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readBytes without table format just returns multiple bytes without being inside a lua table
e.g:
| Code: |
b1,b2,b3,b4=readBytes(0x00400500,4)
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will put the byte of 00400500 at b1, 00400501 at b2, 00400502 at b3 and 00400503 at b4
as for why == returns true no idea, but using == on something that returns multiple results is ambiguous at best
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AylinCE
Grandmaster Cheater Supreme
 Reputation: 35
Joined: 16 Feb 2017
Posts: 1485
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| Posted: Fri Jul 19, 2024 3:10 am Post subject: |
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| Code: | function readHex(address, byte)
local bytestring1={}
local str=''
bytestring1=readBytes(address, tonumber(byte), true)
for i,k in pairs(bytestring1) do
str=str..string.format('%02x ',bytestring1[i])
end
return str:upper()
end
addr = "12569ec0"
print(readHex(addr,1))
print(readHex(addr,2))
print(readHex(addr,3))
print(readHex(addr,20)) |
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ParkourPenguin
I post too much
 Reputation: 150
Joined: 06 Jul 2014
Posts: 4657
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| Posted: Fri Jul 19, 2024 10:01 am Post subject: |
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Not a bug. That's just how multiple values in Lua work. See section 3.4 of the Lua 5.3 reference manual:
https://www.lua.org/manual/5.3/manual.html#3.4
| Code: | function f1()
return 1,2
end
function f2()
return 1,3
end
assert(f1() == f2()) |
In the assert, the expressions `f1()` and `f2()` are adjusted to a single return value. The first value returned is kept and used for the comparison. All others (i.e. 2 and 3 respectively) are discarded. Thus, the comparison becomes `1 == 1` which is true.
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ｃｄ&
Newbie cheater
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Joined: 08 Apr 2023
Posts: 20
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| Posted: Sat Jul 20, 2024 1:26 am Post subject: |
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oh, I understand how it works.
Thank you very much |
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