Cheat Engine :: View topic - lua string>>Intercepting and replacing strings

Cheat Engine
The Official Site of Cheat Engine

FAQ

Memberlist

Usergroups

Profile

lua string>>Intercepting and replacing strings

Cheat Engine Forum Index -> Cheat Engine Lua Scripting

View previous topic :: View next topic

Author

Message

.lua
Expert Cheater

Reputation: 1

Joined: 13 Sep 2018
Posts: 203

Posted: Fri May 31, 2019 2:37 pm Post subject: lua string>>Intercepting and replacing strings

Code:

function getStr(s,t,e,h)
if string.find(s,t) and string.find(s,e) then
if h==nil then
if string.len(e)>=2 then
local t1=string.find(s,t)
local e1=string.find(s,e)-1+string.len(e)
local z1=string.sub(s,t1,e1)
return z1
else
local t2=string.find(s,t)
local e2=string.find(s,e)
local z2=string.sub(s,t2,e2)
return z2
end
else
if string.len(t)>=2 then
local t3=string.find(s,t)+string.len(t)
local e3=string.find(s,e)-1
local z3=string.sub(s,t3,e3)
return z3
else
if string.len(e)>=2 then
local t4=string.find(s,t)+1
local e4=string.find(s,e)-1
local z4=string.sub(s,t4,e4)
return z4
else
local t5=string.find(s,t)+1
local e5=string.find(s,e)-1
local z5=string.sub(s,t5,e5)
return z5
end
end
end
end
end
local s = "Hello, can you help me simplify the code?"
print(getStr(s,'H','code?'))
print(getStr(s,'H','code?',0))

print(getStr(s,', c','the'))
print(getStr(s,'o, ','the',0))

Hello, can you help me simplify the code?

Or you can give me the simplest code you think. Thank you.

panraven
Grandmaster Cheater

Reputation: 62

Joined: 01 Oct 2008
Posts: 959

Posted: Fri May 31, 2019 5:58 pm Post subject:

Code:

The s:find(x) treat x as regular expression instead of plain text, this may cause problem if x contain some regular expression characters. It can be force to plain text by following function.

Code:

function toPlainText(s)return (s:gsub("%W","%%%1"))end

_________________

- Retarded.

Last edited by panraven on Sat Jun 01, 2019 2:22 am; edited 2 times in total

Corroder
Grandmaster Cheater Supreme

Reputation: 75

Joined: 10 Apr 2015
Posts: 1668

Posted: Fri May 31, 2019 10:20 pm Post subject:

My turn:

Code:

local function splitString(str, start, last)
local dummy = string.gsub(str, start, "")
local text = string.gsub(dummy, last, "")
return (text:gsub("^%s*", ""))
end

local str = "Hello, can you help me simplify the code?"

-- Test
print(splitString(str, 'Hello, ', ''))
-- , can you help me simplify the code?
print(splitString(str, 'can', 'you help '))
-- Hello, me simplify the code?
dumb = splitString(str, 'can', 'you help ')
print(splitString(dumb, 'Hello,', 'code%?'))
--me simplify the
print(splitString(str, 'Hel', ''))
-- lo, can you help me simplify the code?

_________________

Stealing Code From Stolen Code...
And Admit It.. Hmmm....Typically LOL

.lua
Expert Cheater

Reputation: 1

Joined: 13 Sep 2018
Posts: 203

Posted: Sat Jun 01, 2019 12:12 am Post subject:

panraven wrote:

Code:

function getStrBoundByHeadTail(s,h,t, excludeHT)
local h1,h2 = s:find(h) -- return beginning and ending index of h if found
local t1,t2 = s:find(t) -- ditto for t
if h1 and t1 then -- find both
local hh = excludeHT and h2+1 or h1 -- ending+1 or beginning index of h
local tt = excludeHT and t1-1 or t2 -- beginning-1 or ending index of t
return s:sub(hh,tt)
end
if not t1 then return s:gsub(h,t) end
end

local s='1@2@3@4@5@6@7@8'

print(getStrBoundByHeadTail(s,'1@','@8',''))
--return:2@3@4@5@6@7（I don't understand）

print(getStrBoundByHeadTail(s,'1','8'))
--return:1@2@3@4@5@6@7@8（①）

print(getStrBoundByHeadTail(s,'@','-'))
--return:1-2-3-4-5-6-7-8（②）

print(getStrBoundByHeadTail(s,'@',''))
--return:blank（Why is it not 12345678? I don't understand）（①）

Please look at the code problem for me again.[/quote]

panraven
Grandmaster Cheater

Reputation: 62

Joined: 01 Oct 2008
Posts: 959

Posted: Sat Jun 01, 2019 1:47 am Post subject:

Quote:

print(getStrBoundByHeadTail(s,'1@','@8',''))
--return:2@3@4@5@6@7（I don't understand）

Any thing in lua is 'true' when interpreted as boolean value except 'false' , 'nil', "NaN" and absent parameter. So last "" in getStrBoundByHeadTail(s,'1@','@8','') means true.

Quote:

print(getStrBoundByHeadTail(s,'1','8'))
--return:1@2@3@4@5@6@7@8（①）

Any problem? exclueHT is false (as absent parameter), so '1' and '8' is not removed.

Quote:

print(getStrBoundByHeadTail(s,'@','-'))

this should return no parameter, since '-' not in s. Somehow in ce print() print nothing while print(nil) return an empty line. I edit the function to return nil instead if no h or t found, since some function may cause error if no parameter, eg. tostring().

Quote:

print(getStrBoundByHeadTail(s,'@',''))

s:find("") always return t1=1,t2=0, if h <found> then result s:sub(hh,tt)
<excludeHT=true>hh = h2+1(>1) tt = t1(is 1)-1=0, hh>tt so return ""
<excludeHT=false>hh = h1(>=1) tt = t2=0. hh>tt so return ""
_________________

- Retarded.

.lua
Expert Cheater

Reputation: 1

Joined: 13 Sep 2018
Posts: 203

Posted: Sat Jun 01, 2019 2:44 am Post subject:

Quote:

Code:

if h1 and t1 then

Change him into

Code:

if h1 and t1 and h~="" and t~="" then

Is that all right?

panraven
Grandmaster Cheater

Reputation: 62

Joined: 01 Oct 2008
Posts: 959

Posted: Sat Jun 01, 2019 6:29 pm Post subject:

sure if it fit your function's usage. _________________ - Retarded.

.lua
Expert Cheater

Reputation: 1

Joined: 13 Sep 2018
Posts: 203

Posted: Sat Jun 01, 2019 8:20 pm Post subject:

panraven wrote:

sure if it fit your function's usage.

Yes, I've tested it and can solve my current string problem for the time being.

Display posts from previous:

	Cheat Engine Forum Index -> Cheat Engine Lua Scripting	All times are GMT - 6 Hours
Page 1 of 1

Jump to:

You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
You cannot attach files in this forum
You can download files in this forum