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MikeNoey
Advanced Cheater
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Joined: 08 Jun 2018
Posts: 64
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 Posted: Sun May 19, 2019 5:27 am Post subject: Multiple string values for one reference ? |
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I'm just wondering if it's possible to assign more than a single value to a reference. So something like this
Reference = 'Yellow' , 'Green' , 'Blue' , 'Orange' , 'Purple'
if (StringAdd ~= Reference) then
print "Not a color"
elseif (StringAdd == Reference) then
print "Is a color"
end
Appreciate the assistance.
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TheyCallMeTim13
Wiki Contributor
 Reputation: 51
Joined: 24 Feb 2017
Posts: 976
Location: Pluto
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| Posted: Sun May 19, 2019 6:19 am Post subject: |
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| Code: | function table.contains(t, element)
for _, value in pairs(t) do
if value == element then
return true
end
end
return false
end
References = { 'Yellow' , 'Green' , 'Blue' , 'Orange' , 'Purple' }
if table.contains(References, StringAdd) then
print('Is in list.')
else
print('Is not in list.')
end |
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Corroder
Grandmaster Cheater Supreme
 Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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| Posted: Sun May 19, 2019 6:59 am Post subject: |
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or using a string list:
| Code: | list = createStringlist()
list.Sorted=true
list.add('Yellow')
list.add('Green')
list.add('Blue')
list.add('Orange')
list.add('Purple')
--print(list.Text )
function add2List(sl, color)
for i = 0,sl.Count-1 do
if sl[i] == color then
print(color..' has on the list')
else
list.add(color)
end
end
end
add2List(list,'Orange') -- Orange has on the list
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Class:Stringlist also have poperties:
| Code: | | setDuplicates() : Sets the duplicates property (dupIgnore, dupAccept, dupError) |
So, when stringlist set duplicate, for example:
| Code: | | list.set duplicate(dupError) |
Will return an error message when trying to add an item already has on the string list.
To use setDuplicate, a string list must be sorted to get it to work.
EDIT:
TO use TheyCallMeTim function, it should be using 'ipairs' if the reference in no particular order.
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MikeNoey
Advanced Cheater
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Joined: 08 Jun 2018
Posts: 64
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| Posted: Mon May 20, 2019 12:40 am Post subject: |
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Thank you guys for the help.
I don't quite understand what you mean about Ipairs @ Corroder
I tried changing the order and it still works with "pairs". Could you maybe show me an example ?
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Corroder
Grandmaster Cheater Supreme
Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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| Posted: Mon May 20, 2019 2:02 am Post subject: |
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For your 'reference' structure now, it will work both pairs or ipairs.
Example :
A Lua Table with flat structure in particular order without key like your 'reference' table.
| Code: | | ref = {'Green', 'Blue', 'Red', 'Orange'} |
For this table above, there are no keys. Both pairs or ipairs, should work.
| Code: | --- print the contains element
-- #1
print(table.concat(ref,", "))
-- result = Green, Blue, Red, Orange
-- or
for k, v in pairs(ref) do
print(v)
end
------------------ result =
-- Green
-- Blue
-- Red
-- Orange
for k, v in ipairs(ref) do
print(v)
end
---------------- result =
-- Green
-- Blue
-- Red
-- Orange
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--#2
Now, let said we have a table with multi array dimensions, for example:
| Code: | local ref = {
{
name = "Fred",
address = "16 Long Street",
phone = "123456"
},
{
name = "Wilma",
address = "16 Long Street",
phone = "123456"
},
{
name = "Barney",
address = "17 Long Street",
phone = "123457"
}
}
for k, v in pairs(ref) do
print(v)
end
--- result = Nothing
for key, value in pairs(ref) do
print(key, value)
end
--- result = 1 2 3 (the index of element)
for index, data in ipairs(ref) do
print(index)
for key, value in pairs(data) do
print('\t', key, value) --- \t to make indent
end
end
result :[[
1
phone 123456
address 16 Long Street
name Fred
2
phone 123456
address 16 Long Street
name Wilma
3
phone 123457
address 17 Long Street
name Barney
]] |
To display nested tables you will have to use nested loops.
Also, use ipairs to iterate through array-like tables, and pairs to iterate through record-like tables.
For more info:
https://www.lua.org/manual/5.3/manual.html#pdf-ipairs
https://www.lua.org/manual/5.3/manual.html#pdf-pairs
http://www.luafaq.org/#T1.10
https://www.youtube.com/watch?v=iaJOA47qYGE
In short, pairs use for unordered table and ipairs use for ordered table.
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MikeNoey
Advanced Cheater
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Joined: 08 Jun 2018
Posts: 64
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| Posted: Tue May 28, 2019 10:07 am Post subject: |
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how would I make this work ? When using 2 string values instead of 1
function table.contains(t, element)
for _, value in pairs(t) do
if value == element then
return true
end
end
return false
end
Time = 'Yellow'
Zone = 'Black'
References = { 'Yellow Black' , 'Green' , 'Blue' , 'Orange' , 'Purple' }
if table.contains (References, Time,Zone) then
print('Is in list.')
else
print('Is not in list.')
end
The result I get is "Is not in list"
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ParkourPenguin
I post too much
 Reputation: 152
Joined: 06 Jul 2014
Posts: 4706
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| Posted: Tue May 28, 2019 11:22 am Post subject: |
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| Code: | function contains(table, ...)
for _,q in ipairs({...}) do
local found = false
for _,v in pairs(table) do
if q == v then found=true; break; end
end
if not found then return false end
end
return true
end |
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