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Anyone mind explaining how this works..

 
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brycez0rz
Grandmaster Cheater
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Joined: 01 Feb 2007
Posts: 910
Location: 14/f/ca

PostPosted: Fri Feb 02, 2007 12:23 am    Post subject: Anyone mind explaining how this works.. Reply with quote

I know my post count will be 2 once this is posted, but I'm not noob, I'm just learning xD

Anways, it was this here
Quote:
0x080 ---> 0x08A
0x081 ---> 0x08B
0x082 ---> 0x08C
(So if your A is 7, then your B MUST BE 8(It cannot be 9, numbers go as 1,2,3 and not 1,3,4) C will be 9)(Use 7, 8 and 9 because some say the earlier numbers and detected)
(DO NOT USE LETTERS, ONLY NUMBERS)
$080 ---> $08A
$081 ---> $08B
$082 ---> $08C
(So if your A is 7, then your B will be 8 and C will be 9)(Use 7, 8 and 9 because some say the earlier numbers and detected)


I think I know what it means, just don't wanna ruin my first CE.

Thanks in advance ^_^

Edit: I'll be refreshing, and waiting for a reply, I have nothing but this to do with my time >_> (I'm not telling you to hurry up btw)
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k!
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Joined: 03 Jan 2007
Posts: 477

PostPosted: Fri Feb 02, 2007 2:40 am    Post subject: Reply with quote

Use AS&R to find the value before the --->, and replace it with the value after the --->.
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brycez0rz
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Posts: 910
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PostPosted: Fri Feb 02, 2007 4:10 am    Post subject: Reply with quote

Thanks, I was just wondering if the
Quote:
(So if your A is 7, then your B MUST BE 8(It cannot be 9, numbers go as 1,2,3 and not 1,3,4) C will be 9)(Use 7, 8 and 9 because some say the earlier numbers and detected)
was like an encryption system - like:
0x080 ---> 0x08A would mean you would make A another character e.g. start at 0 as S, 1 as T, 2 as U, 3 as V etc.
Oh well, thanks again Smile
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