Cheat Engine

Slugsnack · Posted: Sat Sep 05, 2009 11:31 am Post subject:

pointers on all 32 bit systems are 4 byte

Dark Byte · Posted: Sat Sep 05, 2009 12:31 pm Post subject:

to explain further since people still think there's a difference:
A pointer to a 1 byte value is 4 bytes
A pointer to a 2 byte value is 4 bytes
A pointer to a 4 byte value is 4 bytes
A pointer to a 8 byte value is 4 bytes
a pointer to a float is 4 bytes
a pointer to a double is 4 bytes
a pointer to a string is 4 bytes

Slugsnack · Posted: Sat Sep 05, 2009 4:34 pm Post subject:

a pointer is saying the address of an object. so we say the address POINTS TO something. so say we had an object of 1 byte, then to locate WHERE it is in memory, there is an address for that object. the address IS THE POINTER

a pointer is simply a 4 byte value containing the address of an object. a pointer to a pointer would be a 4 byte value that holds the address of the pointer to the object

tomcat · How do I cheat? Reputation: 0 Joined: 09 Oct 2008 Posts: 2

Hi i tried this but now i have one problem. How can i prevent a crash when I try to read an adress that does not exists?
I have 3th level Pointer and the last adress does only exist sometimes ^^

Jani · Posted: Sun Nov 15, 2009 2:54 pm Post subject:

Slugsnack · Posted: Sun Nov 15, 2009 3:12 pm Post subject:

alternatively __try/__except()

Flyte · Posted: Sun Nov 15, 2009 3:17 pm Post subject:

Slugsnack · Posted: Sun Nov 15, 2009 4:27 pm Post subject:

tomcat · How do I cheat? Reputation: 0 Joined: 09 Oct 2008 Posts: 2

can someone show me how to use one of this solutions?
I'm pretty new in c++ and dont get it Sad

elshabory · Newbie cheater Reputation: 0 Joined: 02 Mar 2011 Posts: 20

can you kindly rewrite this code in delphi

dpdsbd · How do I cheat? Reputation: 0 Joined: 12 Feb 2014 Posts: 8

Thank you for the FAQ - however I'm not sure I understood it correctly. I have following values in CE:

(see attachment)

So if I unerstood correctly:

First step (mdnsNSP.dll+0001ED30) gives me 01132380
Second step - 01132380 + 540 should give me 00D4E1A4
When i add them as HEX - [0113280] + 540 = 11328C0, not the value above - what am I doing wrong?

Dark Byte · Posted: Wed Feb 12, 2014 2:40 pm Post subject:

it's [01132380 + 540] not [01132380] + 540

dpdsbd · How do I cheat? Reputation: 0 Joined: 12 Feb 2014 Posts: 8

Ok but what is the real difference - sorry but I'm spend whole day trying to figure it out and going through tons of stuff & tutorials - it being in the brackets means I should add it in a special way?

Dark Byte · Posted: Wed Feb 12, 2014 3:02 pm Post subject:

Read the 4 byte value stored at 01132380 + 540 (So read the 4 bytes at 11328C0 and use that result for the next step)

dpdsbd · How do I cheat? Reputation: 0 Joined: 12 Feb 2014 Posts: 8

Right, I got it now - the problem was that I was using returned value as Hex not as Decimal.

Thank you very much! Karma+1 for you Smile