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[C++] Char array not taken as an argument type.

 
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sven3107
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Joined: 04 Feb 2009
Posts: 118
Location: Belgium
PostPosted: Sun Nov 01, 2009 10:20 am    Post subject: [C++] Char array not taken as an argument type. Reply with quote
Right, I'm doing some basic functions with consoles, but for some reason I get syntax errors when I use this declaration.

Code:
                  void WriteLine(char[] Input)
                  {
                     std::cout<<Input<<std::endl;
                  }


And it returns this error: "error C2146: syntax error : missing ')' before identifier 'Input'"


However, using a fixed size array works just fine.

Code:
                  void WriteLine(char Input[80])
                  {
                     std::cout<<Input<<std::endl;
                  }


Returns no errors.


So my question is: How would I use char[] as input type, since it usually works just fine?
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lurc
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PostPosted: Sun Nov 01, 2009 10:22 am    Post subject: Reply with quote
Code:
void WriteLine(char *Input)
{
   std::cout << Input << std::endl;
}

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smartz993
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PostPosted: Sun Nov 01, 2009 10:24 am    Post subject: This post has 1 review(s) Reply with quote
What you would need to do is pass a reference to the array, so as your argument type ([] is invalid and can't be used) you can make it a pointer by prefixing the variable name with a *.

Code:

void func(char *array)
{
    array[0] = '\0';
}
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sven3107
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PostPosted: Sun Nov 01, 2009 10:24 am    Post subject: Reply with quote
Thanks, but could you explain how using a pointer helps solve the problem?

I don't really like to paste code without understanding the full function.


EDIT: Never mind, sorta slow reply, so I didn't see the second reply.

Thanks.
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Flyte
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PostPosted: Sun Nov 01, 2009 12:48 pm    Post subject: Reply with quote
Since you're using C++ anyways: http://www.cplusplus.com/reference/string/string/
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