Cheat Engine :: View topic - Celsius to Fahrenheight converter error

Cheat Engine
The Official Site of Cheat Engine

FAQ

Memberlist

Usergroups

Profile

Celsius to Fahrenheight converter error

Cheat Engine Forum Index -> General programming

View previous topic :: View next topic

Author

Message

AndrewMan
Grandmaster Cheater Supreme

Reputation: 0

Joined: 01 Aug 2007
Posts: 1257

Posted: Fri Jul 10, 2009 5:25 pm Post subject: Celsius to Fahrenheight converter error

Code:

//Celsius to Fahrenheit July 10, 2009

#include <iostream>
using namespace std;

int Celsius;
int Fahrenheight(int);

int main()
{
cout << "Please enter a Celsius value: ";
   cin >> Celsius;
   int degree = Fahrenheight(degree);
   cout << Celsius << " degrees Celsius is " << degree << " degrees Fahrenheit";
   cin.get();
   cin.get();
   return 0;

}
int Fahrenheight(int degree)
{
return degree = 1.8 * Celsius + 32;
}

I get this error after I type an integer into

Code:

cin >> Celsius;

Run-Time Check Failure #3 - The variable 'degree' is being used without being initialized.

It gives me the option to hit Continue, or Break, and when I hit Continue the code continues on and the program gives me a Fahrenheight value. I dunno why I am getting this error. I am using VC++.
_________________

Every lvl up counts!

HolyBlah
Master Cheater

Reputation: 2

Joined: 24 Aug 2007
Posts: 446

Posted: Fri Jul 10, 2009 5:42 pm Post subject:

Change

Code:

int degree = Fahrenheight(degree);

Code:

int degree = Fahrenheight(Celsius);

AndrewMan
Grandmaster Cheater Supreme

Reputation: 0

Joined: 01 Aug 2007
Posts: 1257

Posted: Fri Jul 10, 2009 5:45 pm Post subject:

HolyBlah wrote:

Change

Code:

int degree = Fahrenheight(degree);

Code:

int degree = Fahrenheight(Celsius);

Ah, thanks dude Very Happy

_________________

Every lvl up counts!

hcavolsdsadgadsg
I'm a spammer

Reputation: 26

Joined: 11 Jun 2007
Posts: 5801

Posted: Fri Jul 10, 2009 10:39 pm Post subject:

It will actually work fine like that, despite the error, because the "Fahrenheight" function doesn't even use it's argument.

Code:

int Fahrenheight(int degree)
{
return degree = 1.8 * Celsius + 32; //degree is nowhere to be found
}

Code:

int degree = Fahrenheight(0);

for example will also get rid of the warning and work fine.

Even more fun is the type conversion warning your code will throw.

Quote:

warning C4244: '=' : conversion from 'double' to 'int', possible loss of data

1.8 is going to be considered a double.
1.8f is going to be seen as a float.

You're trying to return an int though, so the compiler will likely just convert it on it's own, but give you the warning you deserve.

Display posts from previous:

	Cheat Engine Forum Index -> General programming	All times are GMT - 6 Hours
Page 1 of 1

Jump to:

You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
You cannot attach files in this forum
You can download files in this forum