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h4c0r-BG
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Zand
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 Posted: Fri Mar 27, 2009 6:10 am Post subject: |
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Formula to use is
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h4c0r-BG
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| Posted: Fri Mar 27, 2009 7:42 am Post subject: |
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| Quote: | dest refers to the parameter into which the result of the operation will be stored.
src refers to the source of any extra data required by the operation. |
So what value SRC is going to hold. And what are those "-"`es and why "5" ...
And am i going to use this via:
Thank you.
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DeletedUser14087
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| Posted: Fri Mar 27, 2009 7:43 am Post subject: |
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| h4c0r-BG wrote: | | Quote: | dest refers to the parameter into which the result of the operation will be stored.
src refers to the source of any extra data required by the operation. |
So what value SRC is going to hold. And what are those "-"`es and why "5" ...
And am i going to use this via:
Thank you. |
Why use asm/end; ? High-Level (Something Normal Humans Read) are ment to keep you away from Low-Level (Something Chinese Aliens Read), lol.
Last edited by DeletedUser14087 on Fri Mar 27, 2009 7:44 am; edited 1 time in total |
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h4c0r-BG
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| Posted: Fri Mar 27, 2009 7:44 am Post subject: |
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Rot1, I am asking because i do not know how to do it at all.. 
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DeletedUser14087
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| Posted: Fri Mar 27, 2009 7:45 am Post subject: |
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| h4c0r-BG wrote: | | Rot1, I am asking because i do not know how to do it at all.. |
Get on messenger. |
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dnsi0
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| Posted: Fri Mar 27, 2009 7:51 am Post subject: |
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| h4c0r-BG wrote: | | Quote: | dest refers to the parameter into which the result of the operation will be stored.
src refers to the source of any extra data required by the operation. |
So what value SRC is going to hold. And what are those "-"`es and why "5" ...
And am i going to use this via:
Thank you. |
The 5 is there becuase it signals the opcode. The opcode that takes up the jump is 5 bytes E9 ?? ?? ?? ??. |
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Flyte
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| Posted: Fri Mar 27, 2009 12:28 pm Post subject: |
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Algebra, use it.
| Code: | | JUMP_OFFSET = TO - FROM - 5 |
| Code: | | TO = JUMP_OFFSET + FROM + 5 |
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h4c0r-BG
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| Posted: Sat Mar 28, 2009 6:54 am Post subject: |
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Thanks for anyone who willed to help me. If anyone is curious what exactly is the solution:
10000001 - 53 43 03 f0/F0034353 - jmp 00034358
10000006 - 4e 43 03 f0/F003434E - jmp 00034358
FFFFFFFF-10000001=EFFFFFFE
F0034353-EFFFFFFE=34355
34355+3=34358
FFFFFFFF-10000006=EFFFFFF9
F003434E-EFFFFFF9=34355
34355+3=34358
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