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LUA - syntax error - Hex String subtraction

 
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jadereporter
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PostPosted: Tue Sep 20, 2016 8:01 am    Post subject: LUA - syntax error - Hex String subtraction Reply with quote
Hello,

Code:
myscan = AOBScan("50 51 A7 7F 8E 00 00 00");

print(myscan[0]); -- result 8E02C10028... it's OK... all right

print(myscan[0] -0x40); -- syntax error ... it's Not OK .. :(




how to subtract Hex Adress at that value?

I find the lower Hex Adress 64 units (0x40) ...

Another thing. After finding the address should I read the value?

With what command reads the value? (string, float, 8bytes, 4bytes, ect ...)
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ParkourPenguin
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PostPosted: Tue Sep 20, 2016 8:08 am    Post subject: Reply with quote
It's a string. Use type() to get the type of a value and tonumber() to convert a string to a number.
Code:
tonumber(myscan[0],16) - 0x40

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jadereporter
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PostPosted: Tue Sep 20, 2016 8:29 am    Post subject: Reply with quote
Thank you.

It's similar to the Javascript command parseInt(hexString, 16).

Now as I read the value of that address?

The second address has a variable value.
I use the first address that has the same value as always.
But what I read is the second.

** I apologize if I write when you do not understand. I use an English translator.
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ParkourPenguin
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PostPosted: Tue Sep 20, 2016 8:36 am    Post subject: Reply with quote
What is the value type of the second address?
Code:
readInteger(address)  -- 4-byte
readFloat(address)    -- float
readDouble(address)   -- double
readString(address)   -- string
readBytes(address,n)  -- raw bytes

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